Branches - Erika #48
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CheezItMan
reviewed
Sep 19, 2019
| index = 0 | ||
| while index <= list.length | ||
| if list[index] == list[index + 1] | ||
| list.delete_at(index) |
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delete_at shifts each subsequent element left by one index. So that's an O(n) method. Since you have it nested in a loop running n times, remove_duplicates becomes an O(n2) method.
| if prefix[i] != comparison_word[i] | ||
| i -= 1 | ||
| prefix = prefix[0..i] | ||
| if prefix == original |
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How could this if statement be true given the line above.
| # Space Complexity: ? | ||
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| # Time Complexity: O(n * m) |
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