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原文:否者,即TS(T1)<TS(T2),就会保存事务T1的时间戳并终止它,稍后再用相同的时间戳重试事务T1。 这里应该终止的不是T2吗?
The text was updated successfully, but these errors were encountered:
不是的,如果终止的是 T2,那不就是“等待-死亡”的情况了。
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原文:否者,即TS(T1)<TS(T2),就会保存事务T1的时间戳并终止它,稍后再用相同的时间戳重试事务T1。
这里应该终止的不是T2吗?
The text was updated successfully, but these errors were encountered: