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"gsl from" causes "Undefined expression: directory.open (...)" #41
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Can you make a minimal test case, with a directory tree containing gsl -Pieter On Sun, May 18, 2014 at 5:50 AM, Duzy Chan [email protected] wrote:
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Yes, sure. Now I have two versions of it that reproduce the similar errors. I'll pack my latest tree first and then revert a bit to the earlier version. |
Hi Pieter, please check your email, it's sent :) |
OK, so I get the same errors... that's good. No idea what the cause could On Sun, May 18, 2014 at 3:44 PM, Duzy Chan [email protected] wrote:
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directory.open is using the wrong path for some reason:
reports
On Sun, May 18, 2014 at 10:52 PM, Pieter Hintjens [email protected] wrote:
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So there's some error in the directory open function, which is I think On Sun, May 18, 2014 at 11:01 PM, Pieter Hintjens [email protected] wrote:
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Thanks Pieter for the 'error'. The 'error' in the form of "directory.open (my.dirname, error) ?" gave much easier prompt. I think my work could become much easier when errors were like that. Hope that we can find out the cause of the directory.open error. I was trying to go deep into the code, but I think I will need a lot of time to understand the whole. |
Hi, I have have two functions to do code generation recursively on a directory.
But it looks like "gsl from my.filepath" has something wrong with directory.open, please help.
When I use "gsl file.slurp(...)" instead, it seems working fine.
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