README_EN.md

comments	difficulty	edit_url	tags
true	Easy	https://github.com/doocs/leetcode/edit/main/solution/0400-0499/0434.Number%20of%20Segments%20in%20a%20String/README_EN.md	String

434. Number of Segments in a String

中文文档

Description

Given a string s, return the number of segments in the string.

A segment is defined to be a contiguous sequence of non-space characters.

 

Example 1:

Input: s = "Hello, my name is John"
Output: 5
Explanation: The five segments are ["Hello,", "my", "name", "is", "John"]

Example 2:

Input: s = "Hello"
Output: 1

 

Constraints:

• 0 <= s.length <= 300
• s consists of lowercase and uppercase English letters, digits, or one of the following characters "!@#$%^&*()_+-=',.:".
• The only space character in s is ' '.

Solutions

Solution 1

Python3

class Solution:
    def countSegments(self, s: str) -> int:
        return len(s.split())

Java

class Solution {
    public int countSegments(String s) {
        int ans = 0;
        for (String t : s.split(" ")) {
            if (!"".equals(t)) {
                ++ans;
            }
        }
        return ans;
    }
}

C++

class Solution {
public:
    int countSegments(string s) {
        int ans = 0;
        istringstream ss(s);
        while (ss >> s) ++ans;
        return ans;
    }
};

Go

func countSegments(s string) int {
	ans := 0
	for _, t := range strings.Split(s, " ") {
		if len(t) > 0 {
			ans++
		}
	}
	return ans
}

PHP

class Solution {
    /**
     * @param String $s
     * @return Integer
     */
    function countSegments($s) {
        $arr = explode(' ', $s);
        $cnt = 0;
        for ($i = 0; $i < count($arr); $i++) {
            if (strlen($arr[$i]) != 0) {
                $cnt++;
            }
        }
        return $cnt;
    }
}

Solution 2

Python3

class Solution:
    def countSegments(self, s: str) -> int:
        ans = 0
        for i, c in enumerate(s):
            if c != ' ' and (i == 0 or s[i - 1] == ' '):
                ans += 1
        return ans

Java

class Solution {
    public int countSegments(String s) {
        int ans = 0;
        for (int i = 0; i < s.length(); ++i) {
            if (s.charAt(i) != ' ' && (i == 0 || s.charAt(i - 1) == ' ')) {
                ++ans;
            }
        }
        return ans;
    }
}

C++

class Solution {
public:
    int countSegments(string s) {
        int ans = 0;
        for (int i = 0; i < s.size(); ++i) {
            if (s[i] != ' ' && (i == 0 || s[i - 1] == ' ')) {
                ++ans;
            }
        }
        return ans;
    }
};

Go

func countSegments(s string) int {
	ans := 0
	for i, c := range s {
		if c != ' ' && (i == 0 || s[i-1] == ' ') {
			ans++
		}
	}
	return ans
}