README_EN.md

comments	difficulty	edit_url	tags
true	Easy	https://github.com/doocs/leetcode/edit/main/solution/0200-0299/0263.Ugly%20Number/README_EN.md	Math

263. Ugly Number

中文文档

Description

An ugly number is a positive integer which does not have a prime factor other than 2, 3, and 5.

Given an integer n, return true if n is an ugly number.

 

Example 1:

Input: n = 6
Output: true
Explanation: 6 = 2 × 3

Example 2:

Input: n = 1
Output: true
Explanation: 1 has no prime factors.

Example 3:

Input: n = 14
Output: false
Explanation: 14 is not ugly since it includes the prime factor 7.

 

Constraints:

• -231 <= n <= 231 - 1

Solutions

Solution 1

Python3

class Solution:
    def isUgly(self, n: int) -> bool:
        if n < 1:
            return False
        for x in [2, 3, 5]:
            while n % x == 0:
                n //= x
        return n == 1

Java

class Solution {
    public boolean isUgly(int n) {
        if (n < 1) return false;
        while (n % 2 == 0) {
            n /= 2;
        }
        while (n % 3 == 0) {
            n /= 3;
        }
        while (n % 5 == 0) {
            n /= 5;
        }
        return n == 1;
    }
}

C++

class Solution {
public:
    bool isUgly(int n) {
        if (n < 1) return false;
        while (n % 2 == 0) {
            n /= 2;
        }
        while (n % 3 == 0) {
            n /= 3;
        }
        while (n % 5 == 0) {
            n /= 5;
        }
        return n == 1;
    }
};

Go

func isUgly(n int) bool {
	if n < 1 {
		return false
	}
	for _, x := range []int{2, 3, 5} {
		for n%x == 0 {
			n /= x
		}
	}
	return n == 1
}

JavaScript

/**
 * @param {number} n
 * @return {boolean}
 */
var isUgly = function (n) {
    if (n < 1) return false;
    while (n % 2 === 0) {
        n /= 2;
    }
    while (n % 3 === 0) {
        n /= 3;
    }
    while (n % 5 === 0) {
        n /= 5;
    }
    return n === 1;
};

PHP

class Solution {
    /**
     * @param Integer $n
     * @return Boolean
     */
    function isUgly($n) {
        while ($n) {
            if ($n % 2 == 0) {
                $n = $n / 2;
            } elseif ($n % 3 == 0) {
                $n = $n / 3;
            } elseif ($n % 5 == 0) {
                $n = $n / 5;
            } else {
                break;
            }
        }
        return $n == 1;
    }
}