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pdf #1

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wzy816 opened this issue Sep 27, 2019 · 1 comment
Open

pdf #1

wzy816 opened this issue Sep 27, 2019 · 1 comment

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@wzy816
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wzy816 commented Sep 27, 2019

probability = 1/pow((2*math.pi), -d/2) * pow(abs(np.linalg.det(Sk)), -1/2) * \

should it be pow((2math.pi), -d/2) or 1/pow((2math.pi), d/2) ?

@Cheng-Lin-Li
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Cheng-Lin-Li commented Sep 28, 2019 via email

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